What is the inverse of f(x)=f(x)=(x+9)/(x+1) ?

The inverse of f(x)=f(x)=(x+9)/(x+1) is (9-x)/(x-1)

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inverse of f(x)=f(x)=(x+9)/(x+1)

inverse

f (x) = f (x) = \frac{x + 9}{x + 1}

\frac{9 - x}{x - 1}

Solution steps

y = \frac{x + 9}{x + 1}

Replace

x

with

y

x = \frac{y + 9}{y + 1}

Solve for

y, x = \frac{y + 9}{y + 1}

\frac{9 - x}{x - 1}

f (x) = 3^{(2 x)} + 1

f (x) = \frac{1}{3} x^{2} + 5

f (x) = lo g_{2} (lo g_{10} (x))

f (x) = \frac{- 8}{x ^{2} - 4}

\frac{2 y + 6}{3 y + 2}

What is the inverse of f(x)=f(x)=(x+9)/(x+1) ?
The inverse of f(x)=f(x)=(x+9)/(x+1) is (9-x)/(x-1)