What is the inverse of f(x)=3^{(2x)}+1 ?

The inverse of f(x)=3^{(2x)}+1 is (ln(x-1))/(2ln(3))

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inverse of f(x)=3^{(2x)}+1

inverse

f (x) = 3^{(2 x)} + 1

\frac{ln ( x - 1 )}{2 ln ( 3 )}

Solution steps

y = 3^{2 x} + 1

Replace

x

with

y

x = 3^{2 y} + 1

Solve for

y, x = 3^{2 y} + 1

\frac{ln ( x - 1 )}{2 ln ( 3 )}

f (x) = \frac{1}{3} x^{2} + 5

f (x) = lo g_{2} (lo g_{10} (x))

f (x) = \frac{- 8}{x ^{2} - 4}

\frac{2 y + 6}{3 y + 2}

f (x) = f (x) = x^{2} + 2

What is the inverse of f(x)=3^{(2x)}+1 ?
The inverse of f(x)=3^{(2x)}+1 is (ln(x-1))/(2ln(3))