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Popular Calculus Problems
(dy)/(dt)=t^2y^3,y(0)=-1
\frac{dy}{dt}=t^{2}y^{3},y(0)=-1
derivative of (x+1)/(2x^2+1)
derivative\:\frac{x+1}{2x^{2}+1}
derivative of (tan(x)/(sec(x)))
\frac{d}{dx}(\frac{\tan(x)}{\sec(x)})
(\partial)/(\partial x)(arcsec(x+yz))
\frac{\partial\:}{\partial\:x}(\arcsec(x+yz))
derivative of f(x)=(x^2)/2+2/(x^2)
derivative\:f(x)=\frac{x^{2}}{2}+\frac{2}{x^{2}}
integral of (tan^5(x))
\int\:(\tan^{5}(x))dx
derivative of f(x)=e^{x-3}
derivative\:f(x)=e^{x-3}
derivative of e^{6t}
derivative\:e^{6t}
y^'=y-x
y^{\prime\:}=y-x
integral from 0 to 4 of 16-x^3
\int\:_{0}^{4}16-x^{3}dx
(dy)/(dx)-1/x*y-3*x^2=0
\frac{dy}{dx}-\frac{1}{x}\cdot\:y-3\cdot\:x^{2}=0
(dy)/(dx)=((e^x))/(ysqrt(1+y^2))
\frac{dy}{dx}=\frac{(e^{x})}{y\sqrt{1+y^{2}}}
tangent of f(x)=(7x)/(x+4),\at x=3
tangent\:f(x)=\frac{7x}{x+4},\at\:x=3
integral of sin^3(3x)cos^2(3x)
\int\:\sin^{3}(3x)\cos^{2}(3x)dx
tangent of f(x)=(6x)/(x+3),(-1,-3)
tangent\:f(x)=\frac{6x}{x+3},(-1,-3)
integral of e^xsin(3x)
\int\:e^{x}\sin(3x)dx
(\partial)/(\partial z)(x^2z^2sin(4y))
\frac{\partial\:}{\partial\:z}(x^{2}z^{2}\sin(4y))
(\partial}{\partial x}(sin(\frac{2x)/y))
\frac{\partial\:}{\partial\:x}(\sin(\frac{2x}{y}))
derivative of-5w^{-7}+3sqrt(w)
derivative\:-5w^{-7}+3\sqrt{w}
limit as x approaches 1 of x/(x-1)
\lim\:_{x\to\:1}(\frac{x}{x-1})
derivative of f(x)=(7x^2+6)(5x+8+7/x)
derivative\:f(x)=(7x^{2}+6)(5x+8+\frac{7}{x})
derivative of sin^2(y)
derivative\:\sin^{2}(y)
integral of (sin^3(x))/(1-cos(x))
\int\:\frac{\sin^{3}(x)}{1-\cos(x)}dx
integral of sqrt(x)-1/(sqrt(x))
\int\:\sqrt{x}-\frac{1}{\sqrt{x}}dx
integral of (e^{2x}cos(e^{2x}))
\int\:(e^{2x}\cos(e^{2x}))dx
derivative of 1/(x^2+1/(x^3))
\frac{d}{dx}(\frac{1}{x^{2}}+\frac{1}{x^{3}})
x(dy)/(dx)-(1+x)y=xy^2
x\frac{dy}{dx}-(1+x)y=xy^{2}
derivative of f(t)=(t^2-4)/(t-2)
derivative\:f(t)=\frac{t^{2}-4}{t-2}
derivative of 6/(x^2)
derivative\:\frac{6}{x^{2}}
integral of 3xsqrt((3x^2+7))
\int\:3x\sqrt{(3x^{2}+7)}dx
tangent of f(x)=3x^4+2e^x,\at x=0
tangent\:f(x)=3x^{4}+2e^{x},\at\:x=0
inverse oflaplace ((s+3))/(s^2+s+3)
inverselaplace\:\frac{(s+3)}{s^{2}+s+3}
derivative of dy/(dx)-a^2y+b=0
\frac{d}{dx}\frac{dy}{dx}-a^{2}y+b=0
limit as x approaches infinity of (45)/x
\lim\:_{x\to\:\infty\:}(\frac{45}{x})
d/(dt)(4/3 sqrt(t^3))
\frac{d}{dt}(\frac{4}{3}\sqrt{t^{3}})
area y=x+1,y=0,x=0,x=2
area\:y=x+1,y=0,x=0,x=2
inverse oflaplace 6/((s+1)^6)
inverselaplace\:\frac{6}{(s+1)^{6}}
derivative of (4x+7)^3
derivative\:(4x+7)^{3}
integral of xsqrt(x^2+16)
\int\:x\sqrt{x^{2}+16}dx
integral of-xcos(x^2)
\int\:-x\cos(x^{2})dx
d/(dθ)(cos(2θ))
\frac{d}{dθ}(\cos(2θ))
(x^2+1)((dy)/(dx))+xy-x=0
(x^{2}+1)(\frac{dy}{dx})+xy-x=0
derivative of 1/3*x^3
\frac{d}{dx}(\frac{1}{3}\cdot\:x^{3})
derivative of f(x)=e^{x/((x-9))}
derivative\:f(x)=e^{\frac{x}{(x-9)}}
d/(ds)((2s^2)/((s-6)^3))
\frac{d}{ds}(\frac{2s^{2}}{(s-6)^{3}})
1/t (dy)/(dt)-1/(1+t^2)=0,y(0)=1
\frac{1}{t}\frac{dy}{dt}-\frac{1}{1+t^{2}}=0,y(0)=1
limit as t approaches 0 of 1/2 e^{-2t}
\lim\:_{t\to\:0}(\frac{1}{2}e^{-2t})
(\partial)/(\partial x)(4x+6y)
\frac{\partial\:}{\partial\:x}(4x+6y)
integral of e^{-(x+y)}
\int\:e^{-(x+y)}dy
derivative of 2/(2-cos(pix))
\frac{d}{dx}(\frac{2}{2-\cos(πx)})
(\partial)/(\partial x)(-xln(x)+xln(y)+y)
\frac{\partial\:}{\partial\:x}(-x\ln(x)+x\ln(y)+y)
tangent of f(x)=x^2-2x,\at x=-3
tangent\:f(x)=x^{2}-2x,\at\:x=-3
derivative of (-x^2-2x+1/((x^2+1)^2))
\frac{d}{dx}(\frac{-x^{2}-2x+1}{(x^{2}+1)^{2}})
limit as x approaches 2-of x^2-x+2
\lim\:_{x\to\:2-}(x^{2}-x+2)
sum from n=1 to infinity of ((2^n))/(n!)
\sum\:_{n=1}^{\infty\:}\frac{(2^{n})}{n!}
(\partial)/(\partial x)(2xln(xy))
\frac{\partial\:}{\partial\:x}(2x\ln(xy))
integral from 0 to 50 of 0.624x
\int\:_{0}^{50}0.624xdx
area 3x,4-x^2
area\:3x,4-x^{2}
derivative of \sqrt[6]{x}-9/x
\frac{d}{dx}(\sqrt[6]{x}-\frac{9}{x})
3e^{2x}((dy)/(dx))=-4(x/(y^2))
3e^{2x}(\frac{dy}{dx})=-4(\frac{x}{y^{2}})
derivative of 1/(\sqrt[5]{2x-1})
\frac{d}{dx}(\frac{1}{\sqrt[5]{2x-1}})
4y^{''}+26y=0
4y^{\prime\:\prime\:}+26y=0
derivative of y=5x
derivative\:y=5x
integral of (3x^2-6x-7)
\int\:(3x^{2}-6x-7)dx
inverse oflaplace 1/((s^2-4s+5))
inverselaplace\:\frac{1}{(s^{2}-4s+5)}
derivative of sin(3x+3xcos(3x))
\frac{d}{dx}(\sin(3x)+3x\cos(3x))
derivative of x-e^{-x}
\frac{d}{dx}(x-e^{-x})
integral of (3x+2)^{2.4}
\int\:(3x+2)^{2.4}dx
(\partial)/(\partial x)(x^6y-2x^5y^2)
\frac{\partial\:}{\partial\:x}(x^{6}y-2x^{5}y^{2})
tangent of-2x^4+5x^2-3(1)
tangent\:-2x^{4}+5x^{2}-3(1)
derivative of y=e^t
derivative\:y=e^{t}
x^2(dy)/(dx)=y
x^{2}\frac{dy}{dx}=y
tangent of f(x)=12sqrt(x),\at x=9
tangent\:f(x)=12\sqrt{x},\at\:x=9
(t^2+4)y^'+2ty=t^2(t^2+4)
(t^{2}+4)y^{\prime\:}+2ty=t^{2}(t^{2}+4)
tangent of y=x^2+3,(4,19)
tangent\:y=x^{2}+3,(4,19)
integral of (2x^2+x-1)/(x(x^2+1))
\int\:\frac{2x^{2}+x-1}{x(x^{2}+1)}dx
d/(dy)((2x^2-xy+2y^2)/(x-y))
\frac{d}{dy}(\frac{2x^{2}-xy+2y^{2}}{x-y})
x^2+2y^2-2x-8y+6=0(0.3)
x^{2}+2y^{2}-2x-8y+6=0(0.3)
inverse oflaplace 1/(2s^2+1)
inverselaplace\:\frac{1}{2s^{2}+1}
integral from 0 to 2 of 1/(x^2-7x+6)
\int\:_{0}^{2}\frac{1}{x^{2}-7x+6}dx
integral of (sqrt(36x^2-49))/(x^3)
\int\:\frac{\sqrt{36x^{2}-49}}{x^{3}}dx
limit as x approaches pi/2-of sec(x)
\lim\:_{x\to\:\frac{π}{2}-}(\sec(x))
(dy)/(dx)=e^{8x-3y},y(0)=4
\frac{dy}{dx}=e^{8x-3y},y(0)=4
derivative of f(x)=(x^2)/((4+x))
derivative\:f(x)=\frac{x^{2}}{(4+x)}
tangent of-9x^{1/3}+5,\at x=27
tangent\:-9x^{\frac{1}{3}}+5,\at\:x=27
derivative of x^2-2x-2/(x^4)
\frac{d}{dx}(x^{2}-2x-\frac{2}{x^{4}})
integral of+(x^2-1)
\int\:+(x^{2}-1)dx
integral of pi^2
\int\:π^{2}dx
derivative of \sqrt[5]{u}
derivative\:\sqrt[5]{u}
limit as x approaches 3 of x^2+3
\lim\:_{x\to\:3}(x^{2}+3)
(dy)/(dx)=yx^3sin(x^4)
\frac{dy}{dx}=yx^{3}\sin(x^{4})
(dx)/(dt)+(2x)/(300+t)=6
\frac{dx}{dt}+\frac{2x}{300+t}=6
integral of x^{-1/2}*ln(x)
\int\:x^{-\frac{1}{2}}\cdot\:\ln(x)dx
limit as x approaches 0 of (1+4x)^{5/x}
\lim\:_{x\to\:0}((1+4x)^{\frac{5}{x}})
limit as x approaches pi/4 of sec(x)tan(x)
\lim\:_{x\to\:\frac{π}{4}}(\sec(x)\tan(x))
limit as x approaches 0+of ln(sin(x))
\lim\:_{x\to\:0+}(\ln(\sin(x)))
derivative of-x^3+4
\frac{d}{dx}(-x^{3}+4)
(\partial)/(\partial x)(y/(2sqrt(x))-1)
\frac{\partial\:}{\partial\:x}(\frac{y}{2\sqrt{x}}-1)
(dx)/(dt)=x^2
\frac{dx}{dt}=x^{2}
integral of tan(4x)
\int\:\tan(4x)dx
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