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Popular Trigonometry Problems

3sin(2x)-3cos(x)=0	3\sin(2x)-3\cos(x)=0
-20cos^2(x)-36cos(x)=16	-20\cos^{2}(x)-36\cos(x)=16
cos(3x)= 1/2 ,0<= x<2pi	\cos(3x)=\frac{1}{2},0\le\:x<2π
-sin(x)-2cos(x)=1	-\sin(x)-2\cos(x)=1
tan(2x)+1=sec(2x),0<= x<= 2pi	\tan(2x)+1=\sec(2x),0\le\:x\le\:2π
3sin^2(θ)-8sin(θ)+5=0	3\sin^{2}(θ)-8\sin(θ)+5=0
8cos(x)-4=0	8\cos(x)-4=0
sin^2(θ)=5sin(θ)+6	\sin^{2}(θ)=5\sin(θ)+6
2=2sec(x)	2=2\sec(x)
cos(x)-sin(x)=(sqrt(2))/2	\cos(x)-\sin(x)=\frac{\sqrt{2}}{2}
cos^2(θ)=1+sin(θ)	\cos^{2}(θ)=1+\sin(θ)
2/5 cos(x)=(sqrt(2))/5	\frac{2}{5}\cos(x)=\frac{\sqrt{2}}{5}
sin^2(x)=6(cos(-x)+1)	\sin^{2}(x)=6(\cos(-x)+1)
2sin(θ)=3cos(θ)	2\sin(θ)=3\cos(θ)
3sin^2(x)=sin(x)+2	3\sin^{2}(x)=\sin(x)+2
sin(θ)=-7/25 ,cos(θ/2),270<θ<360	\sin(θ)=-\frac{7}{25},\cos(\frac{θ}{2}),270^{\circ\:}<θ<360^{\circ\:}
tan(x)+sin(x)=((sin(x)+1))/(cos(x))	\tan(x)+\sin(x)=\frac{(\sin(x)+1)}{\cos(x)}
solvefor x,cos(2x)=sin(x)	solvefor\:x,\cos(2x)=\sin(x)
-2sin(x)+cos(x)=0	-2\sin(x)+\cos(x)=0
3cos((2pit)/3)+10=11	3\cos(\frac{2πt}{3})+10=11
cos(θ)=(sqrt(6))/6 ,sin(θ)	\cos(θ)=\frac{\sqrt{6}}{6},\sin(θ)
9sec^2(x)-9=0	9\sec^{2}(x)-9=0
4tan(x)-7=3tan(x)-6	4\tan(x)-7=3\tan(x)-6
-6cos(2θ)+2cos(θ)+2=3cos(θ)	-6\cos(2θ)+2\cos(θ)+2=3\cos(θ)
2sqrt(3)cos(2θ)=-3	2\sqrt{3}\cos(2θ)=-3
tan(a)=(-1/4),sec(a)	\tan(a)=(-\frac{1}{4}),\sec(a)
2sin^2(x)+1=0	2\sin^{2}(x)+1=0
sin(x+pi/4)-sin(x-pi/4)=0	\sin(x+\frac{π}{4})-\sin(x-\frac{π}{4})=0
4tan(x)-tan^2(x)=1	4\tan(x)-\tan^{2}(x)=1
solvefor x,arcsin(y)=arcsin(x)+((pi))/4	solvefor\:x,\arcsin(y)=\arcsin(x)+\frac{(π)}{4}
18sin^2(x)-9sin(x)=0	18\sin^{2}(x)-9\sin(x)=0
3sin^2(θ)+6sin(θ)-11=7sin(θ)-9	3\sin^{2}(θ)+6\sin(θ)-11=7\sin(θ)-9
solvefor x,2cos(x)-sqrt(3)=0	solvefor\:x,2\cos(x)-\sqrt{3}=0
tan(θ)=(1.5)/(9.81)	\tan(θ)=\frac{1.5}{9.81}
sin(x)+cos(x)=0,0<= x<= 2pi	\sin(x)+\cos(x)=0,0\le\:x\le\:2π
tan^2(θ)+6tan(θ)+7=0	\tan^{2}(θ)+6\tan(θ)+7=0
cos((pix)/2)=0	\cos(\frac{πx}{2})=0
arccot(x)= pi/2	\arccot(x)=\frac{π}{2}
cos(2θ)+cos(4θ)=0	\cos(2θ)+\cos(4θ)=0
6sin(A)-3=0	6\sin(A)-3=0
2sin^2(2θ)+3sin(2θ)+1=0	2\sin^{2}(2θ)+3\sin(2θ)+1=0
6cos(2x)+cos(2x)=1	6\cos(2x)+\cos(2x)=1
0.8= 1/2 (1-cos(θ/2))	0.8=\frac{1}{2}(1-\cos(\frac{θ}{2}))
2tan^2(x)+tan(x)-2=0	2\tan^{2}(x)+\tan(x)-2=0
3sec(θ)+1=7,0<= θ<2pi	3\sec(θ)+1=7,0\le\:θ<2π
sin(A)cos(A)=sin(A)	\sin(A)\cos(A)=\sin(A)
tan(x/2-pi/4)=1	\tan(\frac{x}{2}-\frac{π}{4})=1
3sin(θ)=1	3\sin(θ)=1
sin(A)tan(A)=sin(A)	\sin(A)\tan(A)=\sin(A)
12sin^2(x)+cos(x)-5=1	12\sin^{2}(x)+\cos(x)-5=1
3tan(θ)+10=0	3\tan(θ)+10=0
sin^2(θ)=6(cos(-θ)-1)	\sin^{2}(θ)=6(\cos(-θ)-1)
-2cos(2θ)+3sin(θ)+4=3	-2\cos(2θ)+3\sin(θ)+4=3
5tan^2(x)-3tan(x)-2=0	5\tan^{2}(x)-3\tan(x)-2=0
-2sin(θ)(1+cos(θ))=0	-2\sin(θ)(1+\cos(θ))=0
2sec^2(2x)=3tan(2x)+1	2\sec^{2}(2x)=3\tan(2x)+1
4cot(x)+5=9	4\cot(x)+5=9
2= 1/2 [1+arctan(1/(1+C))]	2=\frac{1}{2}[1+\arctan(\frac{1}{1+C})]
solvefor x,tan(x)= 1/2	solvefor\:x,\tan(x)=\frac{1}{2}
solvefor t,x=sin^2(t)	solvefor\:t,x=\sin^{2}(t)
2sin^2(θ)-3sin(θ)-2=0,0<= θ<2pi	2\sin^{2}(θ)-3\sin(θ)-2=0,0\le\:θ<2π
sin(θ)+cos(θ)=-sqrt(2)	\sin(θ)+\cos(θ)=-\sqrt{2}
cot(2x)=1.732,0<= x<= 2pi	\cot(2x)=1.732,0\le\:x\le\:2π
cot(θ)=3.2404	\cot(θ)=3.2404
8sin^2(x)=4	8\sin^{2}(x)=4
2+2cos(2x)=0	2+2\cos(2x)=0
cot(θ)=-0.9	\cot(θ)=-0.9
csc(x)-2cot(x)=0	\csc(x)-2\cot(x)=0
1/2-cos(x)=0	\frac{1}{2}-\cos(x)=0
cos^2(x)-sin(x)cos(x)=0	\cos^{2}(x)-\sin(x)\cos(x)=0
cos(θ)sin(θ)=1	\cos(θ)\sin(θ)=1
solvefor x,4sin(x)+2=0	solvefor\:x,4\sin(x)+2=0
sqrt(3)=-tan(x)	\sqrt{3}=-\tan(x)
-tan^2(x)-2tan(x)-1=0	-\tan^{2}(x)-2\tan(x)-1=0
sin(x)= 4/(6sqrt(2))	\sin(x)=\frac{4}{6\sqrt{2}}
cos(5x)=cos(3x)	\cos(5x)=\cos(3x)
2cos(2t)=0	2\cos(2t)=0
4cos^2(θ)=3+3sin(θ)	4\cos^{2}(θ)=3+3\sin(θ)
4cos(3θ)+2sqrt(3)=0	4\cos(3θ)+2\sqrt{3}=0
cos(2θ)+3cos(θ)-1=0	\cos(2θ)+3\cos(θ)-1=0
2sin^2(x)=2-sqrt(3cos(x))	2\sin^{2}(x)=2-\sqrt{3\cos(x)}
2sin(x)+tan(x)=0	2\sin(x)+\tan(x)=0
arctan(x+1)+arctan(x-1)=arctan(12)	\arctan(x+1)+\arctan(x-1)=\arctan(12)
6cos(C)-4=cos(C)-9	6\cos(C)-4=\cos(C)-9
tan^2(x)-3.31tan(x)+1.55=0	\tan^{2}(x)-3.31\tan(x)+1.55=0
sec^2(x)-9=0	\sec^{2}(x)-9=0
cos^2(x)+2sin(x)-1=0	\cos^{2}(x)+2\sin(x)-1=0
6-cos^2(θ)=5	6-\cos^{2}(θ)=5
2sec(x)+2=6	2\sec(x)+2=6
arctan(1/x)=arctan(-x)	\arctan(\frac{1}{x})=\arctan(-x)
14928=(18177)/((1+0.387cos(x)))	14928=\frac{18177}{(1+0.387\cos(x))}
sin^2(θ)-3cos(θ)=4	\sin^{2}(θ)-3\cos(θ)=4
sec^2(x)-2=0,0<= x<= 2pi	\sec^{2}(x)-2=0,0\le\:x\le\:2π
cos^2(x)-2sin(x)=1	\cos^{2}(x)-2\sin(x)=1
1/2 =sin(2θ)	\frac{1}{2}=\sin(2θ)
1-2sin(θ)=-1	1-2\sin(θ)=-1
sin(2x)+sin(x)=sin(3x)	\sin(2x)+\sin(x)=\sin(3x)
sin(2x)=2sqrt(3)sin^2(x)	\sin(2x)=2\sqrt{3}\sin^{2}(x)
cosh(x)=5	\cosh(x)=5
cosh(x)=7	\cosh(x)=7

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